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How do you find the net acceleration of an object with known mass, given opposite horizontal forces acting on the object?
Imagine playing tug of war with a dog over a squirrel chew toy. If you pull the toy with 15 N of force, and the dog pulls the toy with 20 N of force, then what will the acceleration be of the 0.5 kg chew toy?
Summary
- m- mass
- kg- kilograms
- FYOUR- your pulling force
- N- Newtons, the units of force
- FDOG- the dog's pulling force
- aNET- the net acceleration
- m- meters
- s- seconds

Notes
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-
-
- FNET- the net force
- m- mass
- aNET- the net acceleration
-
- aNET- the net acceleration
-
- FNET- the net force
- m- mass
- aNET- the net acceleration
-
- FNET- the net force
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- The force-body diagram is just a diagram of the object with all the forces that act on it
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- FYOUR- your pulling force
- FDOG- the dog's pulling force
- N- Newtons, the units for force
- The positive direction points to the left
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- To add the forces, we add the two opposite force vectors
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- FYOUR- your pulling force
- FDOG- the dog's pulling force
- FNET- the net force
- N- Newtons, the units for force
-
-
- aNET- the net acceleration
- N- newtons
- kg- kilograms
-
- aNET- the net acceleration
- m- meters
- s- seconds
- acceleration points in the positive direction (with the dog) and so it is positive