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How do you solve for displacement of a falling object near Earth, given a start at rest, and time?
You go bowling at a new alley called Galileo's Bowling. Instead of rolling the bowling ball down a lane, you have to go up some stairs and drop the bowling ball onto a set of pins below. If you release the ball and let it fall for 4 seconds before it hits the ground, then what was the height from which you released it?
Summary
- vi- initial velocity
- t- time
- s- seconds
- d- displacement vector
- a- acceleration
- g- acceleration from gravity

Notes
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- The height is just the length of the displacement vector
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- In gravity problems it's really important to define a positive and negative direction
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- Remember that gravity always points down towards the earth
- a- acceleration
- The sign of acceleration is negative because the downward direction is defined to be negative.
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- vi- initial velocity
- m- meters, s- seconds
- t- time
- d- displacement
- a- acceleration
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-
- vi- initial velocity
- d- displacement
- a- acceleration
- t- time
-
- vi- initial velocity
- d- displacement
- a- acceleration
- t- time
-
-
- vi- initial velocity
- d- displacement
- a- acceleration
- t- time
-
-
- d- displacement
- m- meters
- s- seconds
-
- d- displacement
- m- meters
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- m- meters