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How Do You Simplify the Square Root of a Negative Number?
Simplify the square root of -60.
Summary
- The symbol over the -60 is the square root, or radical sign
- -60 has a perfect square factor of 4, so it can be simplified
- If we factor out a -1, then we can take the square root of 60
- The prime factorization of 60 is 2
• 2• 3• 5 - The Product Property allows you to break up the radical
- 'i' is the imaginary unit and equals the square root of -1
- Squaring and taking the square root are opposite operations, so the square root of 22 is 2!
- 'r' can stand for any number

Notes
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- 'Radical' here refers to the square root symbol
- The square root of -60 can be rewritten as the square root of -15*4
- Since -60 has a perfect square factor, we can simplify this further!
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- Factoring out the -1 will let you simplify the positive part of the radicand
- The radicand is the number under the square root symbol
- Now you can focus on the positive 60 under the radical
- A 'radical' is another word for the square root symbol
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- The positive number here is 60
- 2, 3, and 5 are all prime numbers and cannot be factored any further
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- 2, 3, and 5 are all prime numbers and cannot be factored any further
- Since there are two factors of 2, we can rewrite them as one factor with an exponent of 2
- Numbers to the power of 1 have an invisible exponent of 1, like 3 and 5 do here
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- 'Radical' here refers to the square root symbol
- The Product Property allows you to put separate terms under their own radicals
- 3 and 5 are both prime, so we'll leave them together under the same radical
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- Finally, simplify what's under each radical
- 'Radical' here refers to the square root symbol
- 'i' is the imaginary unit and is equal to the square root of -1
- Squaring and taking the square root are opposite operations, so the square root of 22 is 2!
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3
• 5 = 15 - Rewrite everything as 2i times the square root of 15
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- 'r' is a variable that can represent any number here
- Notice how you can pull out a -1 just like we did with -60 in our problem
- Recall that the square root of -1 is equal to the imaginary unit 'i'