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How Do You Find All the Possible Factors of a Trinomial?
Find the possible factors of 6x2+19x+15
Summary
- To figure out the template, look at the signs of the trinomial
- Since both signs are positive, our binomials will both have PLUS signs
- The factors of 6, 1•6 and 2•3, will be the coefficients of our first terms
- The factors of 15, 1•15 and 3•5, will be our second terms
- Now just list all the possible combinations of the factors

Notes
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- We need to look at the signs of our trinomial to determine the template
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- Our last sign is an ADDITION sign
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- If the sign on the trinomial we're factoring is POSITIVE, the two binomials we get when we factor will have the SAME SIGNS
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- Our first sign is also an ADDITION sign
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- Since both of our signs are POSITIVE, we'll have two binomials with ADDITION signs
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- Since both of our signs are POSITIVE, we'll have two binomials with ADDITION signs
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- The factors of 6 will be the coefficients of the first terms of the binomials when we factor
- 6 factors into 1•6 and 2•3
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- These will be the possible coefficients of the first terms of our new binomials
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- The factors of 15 will be the coefficients of the second terms of the binomials when we factor
- 15 factors into 1•15 and 3•5
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- These will be the possible coefficients of the second terms of our new binomials
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- Remember, 6 factored into 1•6 and 2•3
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- Remember, 6 factored into 1•6 and 2•3
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- x is the variable we had in our original trinomial
- 1 and 6, our first set of factors, become the coefficients of the first terms
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- This was the template we figured out before
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- Remember, 15 factored into 1•15 and 3•5
- These will be the second terms of our binomials
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- Remember, 15 factored into 1•15 and 3•5
- These will be the second terms of our binomials
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- Remember, we're looking for ALL the possible combinations
- So if we flip the 1 and the 15, we'll have a different pair of binomials
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- 15 also factored into 3 and 5
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- So 3 and 5 could also be our second terms
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- Remember, we're looking for ALL possible combinations
- So we can switch the second terms to get a new pair of binomials
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- Remember, 6 also factored into 2 and 3
- So 2 and 3 could also be the coefficients of our first terms
- This means we have another set of binomials we need to look at
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- This time, 2 and 3 will be our coefficients
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- 2 and 3 are our coefficients
- We still have x as our variable
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- We need to find all the possible combinations of binomials, with the factors of 15 as our second terms
- Just like before, we'll use 1 and 15 and 3 and 5 for our second terms
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- Remember, we still want to find ALL the possible combinations
- So make sure you flip the last terms as well!
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