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How Do You Solve a More Complicated Interest Problem?
Elana invested a total of $6400. Part of her investment was at 6% interest, and part of her investment was at 8.5% interest. If she made a total of $1035 in interest over the last 30 months, how much money did she invest at each rate?
Summary
- m represents the amount of money invested at 6% interest
- n represents the amount of money invested at 8.5% interest
- We have two equations with two unknowns, so we can solve for m and n
- We have m in terms of n, so we can plug it into the second equation to find n
- Simplify to find that n=1200
- Plug 1200 in for n in the first equation to find that m=5200

Notes
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- m will be one of our variables
- m will represent the amount of money Elana invested at a 6% interest rate
- n will be our other variable
- n will represent the amount of money Elana invested at an 8.5% interest rate
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- Remember, our variables m and n were both parts of her investment
- So if we add them together, we'll get the total amount she invested, $6400
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- Add m and n to get Elana's total investment, which we know is $6400
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- The formula for simple interest is I=prt, where:
- I is the amount of interest earned
- p is the amount of money invested
- r is the interest rate
- t is time in years
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- The formula we have is the formula for interest when there is only one interest rate
- But we can still use it, we just have to adapt it a little to fit our problem
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- ITOT represents the total amount of interest earned
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- We need to find the amount of interest she earned at each rate separately, then add them together
- So one part of our formula will be the interest earned at a 6% rate
- And we'll add that to the interest earned at an 8.5% rate
- This will give us the total amount of interest earned
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- pr1t will be the amount of interest earned at a 6% rate
- p is the amount she invested at 6%
- r1 is the first interest rate, 6%
- t, time, will be the same for both parts, because she invested them both at the same time
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- pr2t will be the amount of interest earned at an 8.5% rate
- p is the amount she invested at 8.5%
- r2 is the second interest rate, 8.5%
- t, time, will be the same for both parts, because she invested them both at the same time
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- This will be the adapted formula we can use to solve our problem
- Notice how it is similar to the formula for simple interest, but now we're adding two things on the right hand side
- We're adding the amounts of interest earned at each separate interest rate
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- ITOT is 1035, the total interest earned
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- Plug 1035 in for ITOT
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- Remember, m represents the amount of money Elana invested at a 6% interest rate
- So p, the amount of money invested in the first part, will be equal to m
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- Remember, m represents the amount of money Elana invested at a 6% interest rate
- So p, the amount of money invested in the first part, will be equal to m
- r1 is the first interest rate, 6%
- But we can't multiply with percents, so we need to convert to a decimal
- Drop the percent sign, move the decimal point two places to the left, and we get 0.06
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- Remember, t represents time in years
- Since our problem gives us time in months, we'll need to convert it to years so we can use it in our formula
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- Remember, t represents time in years
- Since our problem gives us time in months, we'll need to convert it to years so we can use it in our formula
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- To convert months to years:
- Divide the number of months, 30, by the number of months in a year, 12
- 30 divided by 12 is 2.5
- So t will be 2.5 years
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- So the interest earned at a 6% rate can be represented by pr1t
- p=m, our variable that represents the amount of money earned at 6%
- r1=0.06, which is 6%, the interest rate, converted to a decimal
- t=2.5, the number of years the investment earned interest
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- Remember, n represents the amount of money Elana invested at an 8.5% interest rate
- So p, the amount of money invested in the second part, will be equal to n
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- The interest earned at an 8.5% rate can be represented by pr2t
- p=n, our variable that represents the amount of money earned at 8.5%
- r2=0.085, which is 8.5%, the interest rate, converted to a decimal
- t=2.5, the number of years the investment earned interest
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- 1035 was the total amount of interest earned
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- Simplify by multiplying the numbers we have
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- Now the right hand side just has the two variables we defined at the beginning
- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
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- Our unknowns are the variables m and n
- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- Our first equation is m+n=6400
- Our second equation is 1035=m(0.15)+n(0.2125)
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- When we have two equations with two unknowns, we call that a system of linear equations
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- m is the first variable we will solve for
- m represents the amount of money Elana invested at a 6% interest rate
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- We want to get m by itself on one side
- Since subtraction is the opposite of addition, we can subtract n from both sides to move it to the right hand side
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- Now we have m by itself on the left hand side and all the n terms on the right hand side
- So we have m in terms of n
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- Since we found that m=6400-n, we can substitute this value for n in our second equation
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- Since we found that m=6400-n, we can substitute this value for n in our second equation
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- Since we found that m=6400-n, we can substitute this value for n in our second equation
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- m represents the amount of money Elana invested at a 6% interest rate
- n represents the amount of money Elana invested at an 8.5% interest rate
- Since we found that m=6400-n, we can substitute this value for n in our second equation
- So instead of m(0.15), we will have (6400-n)(0.15)
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- n represents the amount of money Elana invested at an 8.5% interest rate
- Multiply 0.15 by each term in the parentheses
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- Like terms are terms that have the same variables raised to the same power
- In our problem, we have two terms that have n raised to the first power, -0.15n and 0.2125n
- We can combine these to simplify our equation
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- Take -0.15n+0.2125n
- Add the coefficients and keep the variable the same
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- n represents the amount of money Elana invested at an 8.5% interest rate
- Now our second equation is fully simplified, so we can solve
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- n represents the amount of money Elana invested at an 8.5% interest rate
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- We want to get n by itself on one side
- Subtraction is the opposite of addition
- So we can get rid of the 960 on the right hand side by subtracting it from both sides
- 1035-960 gives us 75 on the left hand side
- And the 960's cancel on the right hand side to leave us with 0.0624n
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- We want to get n by itself on one side
- Division is the opposite of multiplication
- So we can get rid of the 0.0624 on the right hand side by dividing it from both sides
- 75/0.0624 gives us 1200 on the left hand side
- The 0.0624's cancel on the right hand side to leave us with n
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- n represents the amount of money Elana invested at an 8.5% interest rate
- We have solved for n!
- n equals $1200, the amount Elana originally invested at an 8.5% rate
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- But we're not done yet
- We still need to find m, the amount she invested at a 6% rate
- Since now we have a value for n, 1200, we can plug it into our first equation to find m
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- m represents the amount of money Elana invested at a 6% interest rate
- We can plug the value we found for n, 1200, into our first equation to solve for m
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- m represents the amount of money Elana invested at a 6% interest rate
- We got 6400-n when we solved for m in terms of n
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- We know that n=1200
- So we can plug it into m=6400-n to find m
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- Plugging 1200 in for n gives us m=6400-1200
- 6400-1200=5200
- So m=5200, the amount of money Elana invested at a 6% rate