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How Do You Multiply Quotients of Monomials by Canceling Factors?
Simplify this expression by canceling common factors:
[(2x2y)/(3yz)]•[(9y2z)/(16xd2)]
Summary
- Cancel out any common factors that you can before multiplying
- x2 is the same as x•x, so one of its x's cancels with the x in the denominator
- 9 is the same as 3•3, so one of its 3's cancels with the 3 in the denominator
- We can rewrite the monomials in the numerator and denominator based on what factors we've canceled out
- Everything in in the first monomial in the denominator canceled, so we can just write it as 1

Notes
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- Dividing our fractions can allow us to multiply two simpler fractions than what we started with
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- Factors of a monomial are all the variables or prime numbers that make up the monomial
- For example, the factors of 2x2y are 2, x2 and y
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- To avoid problems, go through one by one and find the numbers and variables that cancel
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- 2 is the first factor of 2x2y
- 16 is the first factor of 16xd2 on the bottom
- The 2 completely cancels out, and the 16 is reduced to 8 in the denominator
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- x2 is a factor of 2x2y
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- x2 is a factor of 2x2y
- x is the second factor in 16xd2
- x2 is just x•x, and one of those x's can cancel with the x in the denominator
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- y is a factor of 2x2y
- There is a y in 2x2y and 3yz, so the two y's can cancel out completely
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- 9 is a factor of 9y2z
- One of the 3's in 9 cancels with the 3 in 3yz
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- y2 is a factor of 9y2z
- We can't use the y in 3yz to cancel with a y in y2 since we've already used the y in 3yz
- This is partly why we suggest going slowly, you don't want to reuse variables
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- z is a factor of both 9y2z and 3yz, so it cancels out completely!
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- We've checked all of the factors in the numerator with all the factors in the denominator
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- Let's make sure we know what we've canceled by rewriting what is left over
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- We canceled out a 2, x, y, 3, and z from the numerator
- That leaves us with an x, 3, y2 on the top
- We canceled out a 3, y, z, 2, and x from the denominator
- That leaves us with 8 and d2 on the bottom
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- The first monomial in the numerator was reduced to just the x
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- The first monomial in the denominator canceled completely, which is why we're putting a 1 there
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- The second monomial in the numerator reduced to 3y2
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- The second monomial in the denominator reduced to 8d2
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- We can now multiply the two monomials in the numerator, and the monomial in the denominator
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- Just multiply everything straight across and combine it into one term
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- To avoid problems, go through one by one and find the numbers and variables that cancel
- After you cancel, rewrite the left over factors so that you can easily multiply them together